ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#196740 | #2909. number | lyp1219 | 100 | 1864ms | 70820kb | C++11 | 2.7kb | 2023-10-30 21:00:50 | 2023-10-30 21:00:51 |
answer
#include<bits/stdc++.h>
using namespace std;
#define ll long long
const int B=1e5,N=5e5+5;
int q;
ll a[N],b[N];
int f[4][73][100005];
inline ll read()
{
char C=getchar();
ll ANS=0,F=1;
while (C<'0'||C>'9')
{
if (C=='-') F=-1;
C=getchar();
}
while (C>='0'&&C<='9')
{
ANS=ANS*10+(C-'0');
C=getchar();
}
return ANS*F;
}
int s[N];
inline int sum(ll x)
{
ll u=x;
if (x<N&&s[x]) return s[x];
int res=0;
while (x) res+=x%10,x/=10;
if (u<N) return s[u]=res;
return res;
}
void init()
{
for (int i=0;i<4;i++)
{
int bas=pow(10,i+2);
for (int j=0;j<=72;j++)
{
for (int k=bas-1;k>=0;k--)
{
int v=k+j+sum(k);
if (v>=bas) f[i][j][k]=v%bas;
else f[i][j][k]=f[i][j][v];
}
}
}
}
#define pii pair<int,int>
#define mp make_pair
#define fi first
#define se second
vector<pii>t[N];
int fa[N],l[N],r[N],dis[N];
bool del[N];
pii v[N];
int find(int x)
{
if (fa[x]==x) return x;
return fa[x]=find(fa[x]);
}
int merge(int x,int y)
{
if (!x||!y) return x+y;
if (v[y]<v[x]) swap(x,y);
r[x]=merge(r[x],y);
if (dis[l[x]]<dis[r[x]]) swap(l[x],r[x]);
dis[x]=dis[r[x]]+1;
return x;
}
void erase(int x)
{
del[x]=1;
fa[l[x]]=fa[r[x]]=fa[x]=merge(l[x],r[x]);
l[x]=r[x]=dis[x]=0;
}
int rt[N],nrt[N];
int MERGE(int x,int y)
{
if (!x||!y) return x+y;
x=find(x),y=find(y);
fa[x]=fa[y]=merge(x,y);
return fa[x];
}
int main()
{
// freopen("number.in","r",stdin);
// freopen("number.out","w",stdout);
q=read();
init();
for (int i=1;i<=q;i++)
{
a[i]=read(),b[i]=read();
if (a[i]/B==b[i]/B) continue;
ll x=a[i]/B,y=a[i]%B;
y=f[3][sum(x)][y],x++;
a[i]=x*B+y;
if (a[i]/B==b[i]/B) continue;
t[x].push_back(mp((int)y,i));
v[i].fi=b[i]/B,v[i].se=i;
}
dis[0]=-1;
for (int i=1;i<=q;i++) fa[i]=i;
//for (int i=1;i<=q;i++) cout << a[i] << endl;
for (ll i=0;i<=99999;i++)
{
for (pii j:t[i])
{
rt[j.fi]=MERGE(rt[j.fi],j.se);
}
for (int j=0;j<100;j++) nrt[j]=0;
for (int j=0;j<100;j++)
{
if (rt[j]==0) continue;
while (1)
{
int x=find(rt[j]);
if (!x) break;
if (v[x].fi<=i)
{
a[v[x].se]=i*B+j;
erase(x);
}
else break;
}
int x=find(rt[j]);
int y=f[3][sum(i)][j];
nrt[y]=MERGE(nrt[y],x);
}
for (int j=0;j<100;j++) rt[j]=nrt[j];
}
//for (int i=1;i<=q;i++) cout << a[i] << endl;
for (int i=1;i<=q;i++)
{
for (int j=2;j>=0;j--)
{
int bas=pow(10,j+2);
while (a[i]/bas!=b[i]/bas)
{
a[i]=a[i]/bas*bas+bas+f[j][sum(a[i]/bas)][a[i]%bas];
}
}
while (a[i]<=b[i]) a[i]+=sum(a[i]);
printf("%lld\n",a[i]);
}
return 0;
}
详细
小提示:点击横条可展开更详细的信息
Subtask #1:
score: 20
Accepted
Test #1:
score: 20
Accepted
time: 301ms
memory: 59548kb
input:
500000 1 1 1 2 1 3 1 4 1 5 1 6 1 7 1 8 1 9 1 10 1 11 1 12 1 13 1 14 1 15 1 16 1 17 1 18 1 19 1 20 1 ...
output:
2 4 4 8 8 8 8 16 16 16 16 16 16 16 16 23 23 23 23 23 23 23 28 28 28 28 28 38 38 38 38 38 38 38 38 38...
result:
ok 500000 lines
Test #2:
score: 0
Accepted
time: 490ms
memory: 59548kb
input:
500000 92 99927 119 99453 481 99268 29 99908 267 99547 835 99500 955 99099 734 99774 306 99883 729 9...
output:
99941 99454 99274 99941 99555 99520 99112 99775 99900 99657 99978 100010 99545 99245 99775 99907 997...
result:
ok 500000 lines
Subtask #2:
score: 25
Accepted
Test #3:
score: 25
Accepted
time: 366ms
memory: 65388kb
input:
500000 1 1 1 2 1 3 1 4 1 5 1 6 1 7 1 8 1 9 1 10 1 11 1 12 1 13 1 14 1 15 1 16 1 17 1 18 1 19 1 20 1 ...
output:
2 4 4 8 8 8 8 16 16 16 16 16 16 16 16 23 23 23 23 23 23 23 28 28 28 28 28 38 38 38 38 38 38 38 38 38...
result:
ok 500000 lines
Subtask #3:
score: 25
Accepted
Test #4:
score: 25
Accepted
time: 37ms
memory: 49872kb
input:
50 4587480273 4587480273 428862505 500400481 6920415626 7358620174 7787875953 7787884613 4542304779 ...
output:
4587480321 500400482 7358620210 7787884620 4542307848 4676070172 909798356 3555627285 9508855574 511...
result:
ok 50 lines
Subtask #4:
score: 30
Accepted
Test #5:
score: 30
Accepted
time: 670ms
memory: 70820kb
input:
500000 1 1 1 2 1 3 1 4 1 5 1 6 1 7 1 8 1 9 1 10 1 11 1 12 1 13 1 14 1 15 1 16 1 17 1 18 1 19 1 20 1 ...
output:
2 4 4 8 8 8 8 16 16 16 16 16 16 16 16 23 23 23 23 23 23 23 28 28 28 28 28 38 38 38 38 38 38 38 38 38...
result:
ok 500000 lines